What is the probability that Bo, Colleen, Jeff and Rohini win the first, second, third and fourth prizes, respectively (in that order), in a drawing if 50 people enter a contest and 4a) no one can win more than one prize. 4b) winning more than one prize is allowed.

### Answers

1/4669920

Step-by-step explanation:

First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

P(n, r) = n!/(n - r)!

Now, the order is important since the first, second, third and fourth prizes are different.

Thus, we need to define the Permutation.

We need to select 4 winners of the 48 people.

Thus, n = 48 and r = 4

Thus;

P(48,4) = 48!/(48 - 4)!

P(48,4) = 4669920

Now, probability is the number of favourable outcomes divided by number of possible outcomes

Thus,

Probability = 1/4669920

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